4y^2+5y+2=0

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Solution for 4y^2+5y+2=0 equation:


Simplifying
4y2 + 5y + 2 = 0

Reorder the terms:
2 + 5y + 4y2 = 0

Solving
2 + 5y + 4y2 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
4 the coefficient of the squared term: 

Divide each side by '4'.
0.5 + 1.25y + y2 = 0

Move the constant term to the right:

Add '-0.5' to each side of the equation.
0.5 + 1.25y + -0.5 + y2 = 0 + -0.5

Reorder the terms:
0.5 + -0.5 + 1.25y + y2 = 0 + -0.5

Combine like terms: 0.5 + -0.5 = 0.0
0.0 + 1.25y + y2 = 0 + -0.5
1.25y + y2 = 0 + -0.5

Combine like terms: 0 + -0.5 = -0.5
1.25y + y2 = -0.5

The y term is 1.25y.  Take half its coefficient (0.625).
Square it (0.390625) and add it to both sides.

Add '0.390625' to each side of the equation.
1.25y + 0.390625 + y2 = -0.5 + 0.390625

Reorder the terms:
0.390625 + 1.25y + y2 = -0.5 + 0.390625

Combine like terms: -0.5 + 0.390625 = -0.109375
0.390625 + 1.25y + y2 = -0.109375

Factor a perfect square on the left side:
(y + 0.625)(y + 0.625) = -0.109375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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